Chapter 1 ? Student Solutions Manual 3. Using the given conversion factors, we find (a) the distance d in rods to be d = 4.0 furlongs =
( 4.0 furlongs )( 201.168 m furlong )
5.0292 m rod
= 160 rods,
(b) and that distance in chains to be d =
( 4.0 furlongs )( 201.168 m furlong )
20.117 m chain
= 40 chains.
5. Various geometric formulas are given in Appendix E. (a) Expressing the radius of the Earth as
R = ( 6.37 ¡¿ 106 m )(10 ?3 km m ) = 6.37 ¡¿ 103 km,
its circumference is s = 2¥ð R = 2¥ð (6.37 ¡¿ 103 km) = 4.00 ¡¿ 104 km. (b) The surface area of Earth is A = 4¥ð R 2 = 4¥ð ( 6.37 ¡¿ 103 km ) = 5.10 ¡¿ 108 km 2 .
2
(c) The volume of Earth is V =
4¥ð 3 4¥ð R = 6.37¡¦(»ý·«)
¡¿ 103 km 3 3
(
)
3
= 1.08 ¡¿ 1012 km3 .
17. None of the clocks advance by exactly 24 h in a 24h period but this is not the most important criterion for judging their quality for measuring time intervals. What is important is that the clock advance by the same amount in each 24h
